Average Rectified Voltage
V_avg = 0.637 × Vpeak
Quick answer
This calculator solves V_avg = (2/π) × V_peak ≈ 0.637 × V_peak for Average Voltage. With Peak Voltage 26.4 V, the result is 16.82 V. It solves in 2 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
The average value of a full-wave rectified sine wave is 2/π (approximately 0.637) times the peak value. This is the DC component of the rectified waveform before filtering. It is important for calculating the DC output of unfiltered rectifiers, calibrating average-responding AC meters, and understanding the relationship between peak, RMS, and average values. Many inexpensive multimeters actually measure the average rectified value and apply a correction factor of 1.11 (π/(2√2)) to display the RMS value, which is only accurate for pure sine waves.
Variables
- V_avg — Average rectified voltage (V)
- V_peak — Peak voltage of the sine wave (V)
Practical Notes
For a half-wave rectifier, V_avg = V_peak/π ≈ 0.318 × V_peak (half the full-wave value). The form factor of a sine wave is V_rms/V_avg = π/(2√2) ≈ 1.111. Average-responding meters reading non-sinusoidal waveforms (square waves, PWM, distorted signals) will give incorrect RMS readings.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| Vavg | Average Voltage | V | pV, nV, µV, mV, V, kV |
| Vpeak | Peak Voltage | V | pV, nV, µV, mV, V, kV |
Step by step
- 1. What you know: Peak Voltage 26.4 V
- 2. The relation: V_avg = (2/π) × V_peak ≈ 0.637 × V_peak
- 3. Substitute: Vpeak = 26.4 V
- 4. Result: Average Voltage = 16.82 V
Worked examples
Minimum range
Given: Peak Voltage 0.726 V
Result: Average Voltage = 0.4625 V
Low range
Given: Peak Voltage 7.26 V
Result: Average Voltage = 4.625 V
Typical
Given: Peak Voltage 26.4 V
Result: Average Voltage = 16.82 V
High range
Given: Peak Voltage 0.506 kV
Result: Average Voltage = 0.3223 kV
Maximum range
Given: Peak Voltage 5.06 kV
Result: Average Voltage = 3.223 kV
Solving for each variable
Solve for Average Voltage
Peak Voltage 0.726 V → 0.4625 V
Solve for Peak Voltage
Average Voltage 0.33 V → 0.5181 V
How Average Voltage changes with Peak Voltage
| Peak Voltage (input) | Average Voltage (result) |
|---|---|
| 2.64 V | 1.682 V |
| 6.6 V | 4.204 V |
| 13.2 V | 8.408 V |
| 19.8 V | 12.61 V |
| 26.4 V | 16.82 V |
| 39.6 V | 25.23 V |
| 52.8 V | 33.63 V |
| 105.6 V | 67.27 V |
| 0.1848 kV | 117.7 V |
| 0.264 kV | 0.1682 kV |
The same result in other units
| Unit | Value |
|---|---|
| mV | 16820 |
| V | 16.82 |
| kV | 0.01682 |
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<p><a href="https://vbatpower.com/formulas/ac-average-rectified/">Average Rectified Voltage</a> Calculator by vbatpower.com</p>Frequently asked questions
How do you calculate Average Rectified Voltage?
Use V_avg = (2/π) × V_peak ≈ 0.637 × V_peak. With Peak Voltage 26.4 V, Average Voltage works out to 16.82 V.
What is the formula for Average Rectified Voltage?
The formula is V_avg = (2/π) × V_peak ≈ 0.637 × V_peak. The average value of a full-wave rectified sine wave is 2/π (approximately 0.637) times the peak value.
How do you find Peak Voltage when you know the other values?
Rearrange for Peak Voltage: with Average Voltage 0.33 V, Peak Voltage is 0.5181 V.
What units does Average Rectified Voltage use?
Average Voltage is shown in mV, V, kV. Values are held in SI base units internally, so you can mix prefixes without converting by hand.
Related Concepts
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