Bridge Rectifier Peak Output

Vdc = Vpeak − 2 · Vdiode

Quick answer

This calculator solves Vdc(peak) = Vpeak − 2 × Vdiode for DC Output (peak). With Transformer Peak 26.4 V, Diode Drop 56.4 V, the result is -86.4 V. It solves in 3 directions, so you can enter the values you have and get the one you need.

Calculator

DC Output (peak) (V)
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Formula

Vdc(peak) = Vpeak − 2 × Vdiode

Description

In a full bridge rectifier with a reservoir capacitor, two diodes conduct in series on each half cycle, so the capacitor charges to the transformer peak voltage minus two diode drops. This peak value, not the averaged Vdc, is what a capacitor-input filter actually delivers under light load. It sets the no-load output and the voltage rating of downstream components.

Variables

  • Vdc — Peak DC at the reservoir capacitor (V)
  • Vpeak — Peak secondary voltage = √2 × Vrms (V)
  • Vdiode — Forward drop per diode (~0.7–1 V)

Practical Notes

Use ~1 V per diode for ordinary silicon at current, or ~0.4 V for Schottky. Under load the average output drops below this peak by the ripple; size the transformer for the loaded, not the no-load, voltage.

Symbols and units

Symbol Meaning Default unit Accepted units
Vdc DC Output (peak) V pV, nV, µV, mV, V, kV
Vpeak Transformer Peak V pV, nV, µV, mV, V, kV
Vdiode Diode Drop V pV, nV, µV, mV, V, kV

Step by step

  1. 1. What you know: Transformer Peak 26.4 V, Diode Drop 56.4 V
  2. 2. The relation: Vdc(peak) = Vpeak − 2 × Vdiode
  3. 3. Substitute: Vpeak = 26.4 V, Vdiode = 56.4 V
  4. 4. Result: DC Output (peak) = -86.4 V

Worked examples

Minimum range

Given: Transformer Peak 0.726 V, Diode Drop 1.55 V

Result: DC Output (peak) = -2.374 V

Low range

Given: Transformer Peak 7.26 V, Diode Drop 15.5 V

Result: DC Output (peak) = -23.74 V

Typical

Given: Transformer Peak 26.4 V, Diode Drop 56.4 V

Result: DC Output (peak) = -86.4 V

High range

Given: Transformer Peak 0.506 kV, Diode Drop 1.08 kV

Result: DC Output (peak) = -1.654 kV

Maximum range

Given: Transformer Peak 5.06 kV, Diode Drop 10.8 kV

Result: DC Output (peak) = -16.54 kV

Solving for each variable

Solve for DC Output (peak)

Transformer Peak 0.726 V, Diode Drop 1.55 V → -2.374 V

Solve for Transformer Peak

DC Output (peak) 0.33 V, Diode Drop 1.55 V → 3.43 V

Solve for Diode Drop

DC Output (peak) 0.33 V, Transformer Peak 0.726 V → 0.198 V

How DC Output (peak) changes with Transformer Peak

Transformer Peak (input) DC Output (peak) (result)
2.64 V -110.2 V
6.6 V -106.2 V
13.2 V -99.6 V
19.8 V -93 V
26.4 V -86.4 V
39.6 V -73.2 V
52.8 V -60 V
105.6 V -7.2 V
0.1848 kV 72 V
0.264 kV 151.2 V

The same result in other units

Unit Value
mV -86400
V -86.4
kV -0.0864

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Frequently asked questions

How do you calculate Bridge Rectifier Peak Output?

Use Vdc(peak) = Vpeak − 2 × Vdiode. With Transformer Peak 26.4 V, Diode Drop 56.4 V, DC Output (peak) works out to -86.4 V.

What is the formula for Bridge Rectifier Peak Output?

The formula is Vdc(peak) = Vpeak − 2 × Vdiode. In a full bridge rectifier with a reservoir capacitor, two diodes conduct in series on each half cycle, so the capacitor charges to the transformer peak voltage minus two diode drops.

How do you find Transformer Peak when you know the other values?

Rearrange for Transformer Peak: with DC Output (peak) 0.33 V, Diode Drop 1.55 V, Transformer Peak is 3.43 V.

How do you find Diode Drop when you know the other values?

Rearrange for Diode Drop: with DC Output (peak) 0.33 V, Transformer Peak 0.726 V, Diode Drop is 0.198 V.

What units does Bridge Rectifier Peak Output use?

DC Output (peak) is shown in mV, V, kV. Values are held in SI base units internally, so you can mix prefixes without converting by hand.

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