Full-Wave Rectifier DC Output
Vdc = 2 · Vpeak / π
Quick answer
This calculator solves Vdc = 2 × Vpeak / π = 0.637 × Vpeak for Average DC Voltage. With Peak Voltage 26.4 V, the result is 16.81 V. It solves in 2 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
A full-wave rectifier (bridge or centre-tapped) inverts the negative half-cycles instead of blocking them, so its average DC output is twice that of a half-wave circuit—about 64% of the peak. Both halves of the waveform deliver current, doubling the ripple frequency and greatly easing filtering. This is the standard topology for linear power supplies.
Variables
- Vdc — Average DC output voltage (V)
- Vpeak — Peak of the rectified AC (V)
Practical Notes
Ripple frequency is twice the line frequency (100/120 Hz), so a smaller reservoir capacitor achieves the same ripple. Subtract diode drops (one for centre-tap, two for bridge) to get the loaded peak.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| Vdc | Average DC Voltage | V | pV, nV, µV, mV, V, kV |
| Vpeak | Peak Voltage | V | pV, nV, µV, mV, V, kV |
Step by step
- 1. What you know: Peak Voltage 26.4 V
- 2. The relation: Vdc = 2 × Vpeak / π = 0.637 × Vpeak
- 3. Substitute: Vpeak = 26.4 V
- 4. Result: Average DC Voltage = 16.81 V
Worked examples
Minimum range
Given: Peak Voltage 0.726 V
Result: Average DC Voltage = 0.4622 V
Low range
Given: Peak Voltage 7.26 V
Result: Average DC Voltage = 4.622 V
Typical
Given: Peak Voltage 26.4 V
Result: Average DC Voltage = 16.81 V
High range
Given: Peak Voltage 0.506 kV
Result: Average DC Voltage = 0.3221 kV
Maximum range
Given: Peak Voltage 5.06 kV
Result: Average DC Voltage = 3.221 kV
Solving for each variable
Solve for Average DC Voltage
Peak Voltage 0.726 V → 0.4622 V
Solve for Peak Voltage
Average DC Voltage 0.33 V → 0.5184 V
How Average DC Voltage changes with Peak Voltage
| Peak Voltage (input) | Average DC Voltage (result) |
|---|---|
| 2.64 V | 1.681 V |
| 6.6 V | 4.202 V |
| 13.2 V | 8.403 V |
| 19.8 V | 12.61 V |
| 26.4 V | 16.81 V |
| 39.6 V | 25.21 V |
| 52.8 V | 33.61 V |
| 105.6 V | 67.23 V |
| 0.1848 kV | 117.6 V |
| 0.264 kV | 0.1681 kV |
The same result in other units
| Unit | Value |
|---|---|
| mV | 16810 |
| V | 16.81 |
| kV | 0.01681 |
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<p><a href="https://vbatpower.com/formulas/fullwave-dc-output/">Full-Wave Rectifier DC Output</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate Full-Wave Rectifier DC Output?
Use Vdc = 2 × Vpeak / π = 0.637 × Vpeak. With Peak Voltage 26.4 V, Average DC Voltage works out to 16.81 V.
How do you calculate calculate dc current of fullwave rectifier?
Rearrange for Average DC Voltage: with Peak Voltage 7.26 V, Average DC Voltage is 4.622 V.
What is the formula for Full-Wave Rectifier DC Output?
The formula is Vdc = 2 × Vpeak / π = 0.637 × Vpeak. A full-wave rectifier (bridge or centre-tapped) inverts the negative half-cycles instead of blocking them, so its average DC output is twice that of a half-wave circuit—about 64% of the peak.
How do you find Peak Voltage when you know the other values?
Rearrange for Peak Voltage: with Average DC Voltage 0.33 V, Peak Voltage is 0.5184 V.
What units does Full-Wave Rectifier DC Output use?
Average DC Voltage is shown in mV, V, kV. Values are held in SI base units internally, so you can mix prefixes without converting by hand.
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