Magnetic Field Strength (H)
H = N · I / l
Quick answer
This calculator solves H = N × I / l for Field Strength. With Number of Turns 0.5, Current 2 A, Path Length 10 mm, the result is 1 A/cm. It solves in 4 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
Magnetic field strength (or magnetizing force) H is the MMF per unit length of the magnetic path. It describes how hard the coil drives the magnetic field, independent of the core material. The resulting flux density follows from B = µ₀µr·H, so H is the cause and B is the effect. It is central to reading B–H magnetization curves.
Variables
- H — Magnetic field strength (A/m)
- N — Number of turns
- I — Current (A)
- l — Magnetic path length (m)
Practical Notes
On a B–H curve the material saturates when increasing H no longer increases B. For a solenoid H = nI where n is turns per metre; for a toroid l is the mean magnetic path length.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| H | Field Strength | A/m | A/m, A/cm, kA/m |
| N | Number of Turns | — | — |
| I | Current | A | pA, nA, µA, mA, A, kA |
| l | Path Length | mm | mm, cm, m, km |
Step by step
- 1. What you know: Number of Turns 0.5, Current 2 A, Path Length 10 mm
- 2. The relation: H = N × I / l
- 3. Substitute: N = 0.5, I = 2 A, l = 10 mm
- 4. Result: Field Strength = 1 A/cm
Worked examples
Minimum range
Given: Number of Turns 0.025, Current 2 mA, Path Length 0.1 mm
Result: Field Strength = 0.5 A/m
Low range
Given: Number of Turns 0.25, Current 20 mA, Path Length 1 mm
Result: Field Strength = 5 A/m
Typical
Given: Number of Turns 0.5, Current 2 A, Path Length 10 mm
Result: Field Strength = 1 A/cm
High range
Given: Number of Turns 0.8, Current 100 A, Path Length 10 cm
Result: Field Strength = 8 A/cm
Maximum range
Given: Number of Turns 8, Current 1 kA, Path Length 1 m
Result: Field Strength = 8 kA/m
Solving for each variable
Solve for Field Strength
Number of Turns 0.025, Current 2 mA, Path Length 0.1 mm → 0.5 A/m
Solve for Number of Turns
Field Strength 10 A/m, Current 2 mA, Path Length 0.1 mm → 0.5
Solve for Current
Field Strength 10 A/m, Number of Turns 0.025, Path Length 0.1 mm → 40 mA
Solve for Path Length
Field Strength 10 A/m, Number of Turns 0.025, Current 2 mA → 0.005 mm
How Field Strength changes with Number of Turns
| Number of Turns (input) | Field Strength (result) |
|---|---|
| 0.05 | 10 A/m |
| 0.125 | 25 A/m |
| 0.25 | 50 A/m |
| 0.375 | 0.75 A/cm |
| 0.5 | 1 A/cm |
| 0.75 | 1.5 A/cm |
| 1 | 2 A/cm |
| 2 | 4 A/cm |
| 3.5 | 7 A/cm |
| 5 | 10 A/cm |
The same result in other units
| Unit | Value |
|---|---|
| A/m | 100 |
| A/cm | 1 |
| kA/m | 0.1 |
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<p><a href="https://vbatpower.com/formulas/magnetic-field-strength/">Magnetic Field Strength (H)</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate Magnetic Field Strength (H)?
Use H = N × I / l. With Number of Turns 0.5, Current 2 A, Path Length 10 mm, Field Strength works out to 1 A/cm.
What is the formula for Magnetic Field Strength (H)?
The formula is H = N × I / l. Magnetic field strength (or magnetizing force) H is the MMF per unit length of the magnetic path.
How do you find Number of Turns when you know the other values?
Rearrange for Number of Turns: with Field Strength 10 A/m, Current 2 mA, Path Length 0.1 mm, Number of Turns is 0.5.
How do you find Current when you know the other values?
Rearrange for Current: with Field Strength 10 A/m, Number of Turns 0.025, Path Length 0.1 mm, Current is 40 mA.
What units does Magnetic Field Strength (H) use?
Field Strength is shown in A/m, A/cm, kA/m. Values are held in SI base units internally, so you can mix prefixes without converting by hand.
Related Concepts
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