Parallel Inductance
1/Ltotal = 1/L1 + 1/L2 + ... + 1/Ln
Quick answer
This calculator solves 1/Ltotal = 1/L1 + 1/L2 + ... + 1/Ln for 1/Ltotal. With Inductor Values 100 µH, 0.22 mH, 0.47 mH, the result is 6 × 10⁻⁵.
Calculator
Formula
Description
Parallel inductors combine using the reciprocal formula, identical to how parallel resistors combine. The total inductance is always less than the smallest individual inductor. This occurs because parallel paths allow current to distribute across multiple inductors, reducing the total magnetic energy stored for a given total current. As with series inductance, this formula assumes no mutual coupling between inductors. Parallel inductors are less common in practice than series, but are used in current sharing applications and sometimes in filter designs.
Variables
- Ltotal — Total equivalent inductance (H)
- L1, L2, ... Ln — Individual inductor values (H)
Practical Notes
Parallel inductors can share DC current load, which is useful when a single inductor cannot handle the required current without saturating. Ensure the inductors are from the same manufacturing batch or have matched values to prevent current imbalance.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| values | Inductor Values | µH | nH, µH, mH, H |
Step by step
- 1. What you know: Inductor Values 100 µH, 0.22 mH, 0.47 mH
- 2. The relation: 1/Ltotal = 1/L1 + 1/L2 + ... + 1/Ln
- 3. Substitute: values = 100 µH, 0.22 mH, 0.47 mH
- 4. Result: 1/Ltotal = 6 × 10⁻⁵
Totals for common combinations
| Components | Values | Total |
|---|---|---|
| 2 | 100 µH + 100 µH | 50 µH |
| 2 | 100 µH + 0.22 mH | 68.75 µH |
| 2 | 100 µH + 1 mH | 90.91 µH |
| 3 | 100 µH + 100 µH + 100 µH | 33.33 µH |
| 3 | 100 µH + 0.22 mH + 0.47 mH | 59.98 µH |
| 4 | 100 µH + 100 µH + 100 µH + 100 µH | 25 µH |
| 4 | 100 µH + 0.22 mH + 0.47 mH + 1 mH | 56.58 µH |
| 5 | 100 µH + 100 µH + 100 µH + 100 µH + 100 µH | 20 µH |
Worked examples
Minimum range
Given: Inductor Values 100 µH, 0.22 mH, 0.47 mH
Result: 1/Ltotal = 6 × 10⁻⁵
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<p><a href="https://vbatpower.com/formulas/parallel-inductance/">Parallel Inductance</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate Parallel Inductance?
Use 1/Ltotal = 1/L1 + 1/L2 + ... + 1/Ln. With Inductor Values 100 µH, 0.22 mH, 0.47 mH, 1/Ltotal works out to 6 × 10⁻⁵.
What is the formula for Parallel Inductance?
The formula is 1/Ltotal = 1/L1 + 1/L2 + ... + 1/Ln. Parallel inductors combine using the reciprocal formula, identical to how parallel resistors combine.
Related Concepts
All Inductors formulas →Need more features?
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