Bridged-T Bridge Resistor
Rb = Z · (K − 1)
Quick answer
This calculator solves Rb = Z × (K − 1) for Bridge Resistor. With Characteristic Impedance 1.03 kΩ, Attenuation 20 dB, the result is 9.27 kΩ. It solves in 2 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
A bridged-T attenuator keeps the two series arms equal to the characteristic impedance Z and varies only two resistors—the bridge resistor across the top and the shunt resistor to ground—to set the attenuation while staying matched. This formula gives the bridge resistor. Because only two resistors change with attenuation, the bridged-T is the basis of constant-impedance variable (stepped) attenuators.
Variables
- Rb — Bridge resistor across the series arms (Ω)
- Z — Characteristic impedance = series-arm value (Ω)
- dB — Desired attenuation; K = 10^(dB/20)
Practical Notes
The matching shunt resistor is Rs = Z/(K−1), so Rb × Rs = Z². Switching just these two resistors gives calibrated step attenuators with constant input/output impedance.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| Rb | Bridge Resistor | Ω | mΩ, Ω, kΩ, MΩ |
| Z | Characteristic Impedance | Ω | mΩ, Ω, kΩ, MΩ |
| dB | Attenuation | dB | dB |
Step by step
- 1. What you know: Characteristic Impedance 1.03 kΩ, Attenuation 20 dB
- 2. The relation: Rb = Z × (K − 1)
- 3. Substitute: Z = 1.03 kΩ, dB = 20 dB
- 4. Result: Bridge Resistor = 9.27 kΩ
Nearest standard component values
| Series | Nearest value | Error |
|---|---|---|
| E12 | 10 kΩ | 7.9% |
| E24 | 9.1 kΩ | 1.8% |
Worked examples
Minimum range
Given: Characteristic Impedance 2.2 Ω, Attenuation 0.3 dB
Result: Bridge Resistor = 77.31 mΩ
Low range
Given: Characteristic Impedance 22 Ω, Attenuation 3 dB
Result: Bridge Resistor = 9.076 Ω
Typical
Given: Characteristic Impedance 1.03 kΩ, Attenuation 20 dB
Result: Bridge Resistor = 9.27 kΩ
High range
Given: Characteristic Impedance 10.3 kΩ, Attenuation 60 dB
Result: Bridge Resistor = 10.29 MΩ
Maximum range
Given: Characteristic Impedance 103 Ω, Attenuation 0.6 dB
Result: Bridge Resistor = 7.366 Ω
Solving for each variable
Solve for Bridge Resistor
Characteristic Impedance 2.2 Ω, Attenuation 0.3 dB → 77.31 mΩ
Solve for Characteristic Impedance
Bridge Resistor 1 Ω, Attenuation 0.3 dB → 28.46 Ω
How Bridge Resistor changes with Characteristic Impedance
| Characteristic Impedance (input) | Bridge Resistor (result) |
|---|---|
| 103 Ω | 0.927 kΩ |
| 0.2575 kΩ | 2.318 kΩ |
| 0.515 kΩ | 4.635 kΩ |
| 0.7725 kΩ | 6.953 kΩ |
| 1.03 kΩ | 9.27 kΩ |
| 1.545 kΩ | 13.91 kΩ |
| 2.06 kΩ | 18.54 kΩ |
| 4.12 kΩ | 37.08 kΩ |
| 7.21 kΩ | 64.89 kΩ |
| 10.3 kΩ | 92.7 kΩ |
The same result in other units
| Unit | Value |
|---|---|
| mΩ | 9270000 |
| Ω | 9270 |
| kΩ | 9.27 |
| MΩ | 0.00927 |
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<p><a href="https://vbatpower.com/formulas/bridged-t-bridge-resistor/">Bridged-T Bridge Resistor</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate Bridged-T Bridge Resistor?
Use Rb = Z × (K − 1). With Characteristic Impedance 1.03 kΩ, Attenuation 20 dB, Bridge Resistor works out to 9.27 kΩ.
What is the formula for Bridged-T Bridge Resistor?
The formula is Rb = Z × (K − 1). A bridged-T attenuator keeps the two series arms equal to the characteristic impedance Z and varies only two resistors—the bridge resistor across the top and the shunt resistor to ground—to set the attenuation while staying matched.
How do you find Characteristic Impedance when you know the other values?
Rearrange for Characteristic Impedance: with Bridge Resistor 1 Ω, Attenuation 0.3 dB, Characteristic Impedance is 28.46 Ω.
What units does Bridged-T Bridge Resistor use?
Bridge Resistor is shown in mΩ, Ω, kΩ, MΩ. Values are held in SI base units internally, so you can mix prefixes without converting by hand.
Related Concepts
All Attenuators & Pads formulas →Need more features?
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