Small-Signal Emitter Resistance

re = VT / Ie

Quick answer

This calculator solves re = VT / Ie (≈ 25 mV / Ie) for Emitter Resistance. With Thermal Voltage 0.6 V, Emitter Current 20 mA, the result is 30 Ω. It solves in 3 directions, so you can enter the values you have and get the one you need.

Calculator

Emitter Resistance (Ω)
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Formula

re = VT / Ie (≈ 25 mV / Ie)

Description

The intrinsic small-signal emitter resistance of a bipolar transistor is the thermal voltage divided by the DC emitter current. It is not a physical resistor but the dynamic resistance of the base–emitter junction, and it sets the maximum voltage gain of a common-emitter stage (Av = −Rc/re). Higher bias current lowers re and raises gain but also raises power.

Variables

  • re — Small-signal emitter resistance (Ω)
  • VT — Thermal voltage (≈25–26 mV)
  • Ie — DC emitter current (A)

Practical Notes

At 1 mA, re ≈ 25 Ω. Because re depends on bias current, an undegenerated common-emitter stage has gain that varies with operating point and temperature; an external emitter resistor stabilises it.

Symbols and units

Symbol Meaning Default unit Accepted units
re Emitter Resistance Ω mΩ, Ω, kΩ, MΩ
Vt Thermal Voltage mV pV, nV, µV, mV, V, kV
Ie Emitter Current mA pA, nA, µA, mA, A, kA

Step by step

  1. 1. What you know: Thermal Voltage 0.6 V, Emitter Current 20 mA
  2. 2. The relation: re = VT / Ie (≈ 25 mV / Ie)
  3. 3. Substitute: Vt = 0.6 V, Ie = 20 mA
  4. 4. Result: Emitter Resistance = 30 Ω

Related quantities from the same inputs

  • P = V × I = 12 mW

Nearest standard component values

Series Nearest value Error
E12 27 Ω 10%
E24 30 Ω 0%

Worked examples

Minimum range

Given: Thermal Voltage 10 mV, Emitter Current 100 µA

Result: Emitter Resistance = 100 Ω

Low range

Given: Thermal Voltage 100 mV, Emitter Current 1 mA

Result: Emitter Resistance = 100 Ω

Typical

Given: Thermal Voltage 0.6 V, Emitter Current 20 mA

Result: Emitter Resistance = 30 Ω

High range

Given: Thermal Voltage 0.9 V, Emitter Current 0.5 A

Result: Emitter Resistance = 1.8 Ω

Maximum range

Given: Thermal Voltage 9 V, Emitter Current 5 A

Result: Emitter Resistance = 1.8 Ω

Solving for each variable

Solve for Emitter Resistance

Thermal Voltage 10 mV, Emitter Current 100 µA → 100 Ω

Solve for Thermal Voltage

Emitter Resistance 1 Ω, Emitter Current 100 µA → 100 µV

Solve for Emitter Current

Emitter Resistance 1 Ω, Thermal Voltage 10 mV → 10 mA

How Emitter Resistance changes with Thermal Voltage

Thermal Voltage (input) Emitter Resistance (result)
60 mV 3 Ω
150 mV 7.5 Ω
0.3 V 15 Ω
0.45 V 22.5 Ω
0.6 V 30 Ω
0.9 V 45 Ω
1.2 V 60 Ω
2.4 V 120 Ω
4.2 V 0.21 kΩ
6 V 0.3 kΩ

The same result in other units

Unit Value
mΩ 30000
Ω 30
kΩ 0.03

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Frequently asked questions

How do you calculate Small-Signal Emitter Resistance?

Use re = VT / Ie (≈ 25 mV / Ie). With Thermal Voltage 0.6 V, Emitter Current 20 mA, Emitter Resistance works out to 30 Ω.

How do you calculate re = vt / ie small signal emitter resistance calculation?

Rearrange for Emitter Resistance: with Thermal Voltage 100 mV, Emitter Current 1 mA, Emitter Resistance is 100 Ω.

What is the formula for Small-Signal Emitter Resistance?

The formula is re = VT / Ie (≈ 25 mV / Ie). The intrinsic small-signal emitter resistance of a bipolar transistor is the thermal voltage divided by the DC emitter current.

How do you find Thermal Voltage when you know the other values?

Rearrange for Thermal Voltage: with Emitter Resistance 1 Ω, Emitter Current 100 µA, Thermal Voltage is 100 µV.

How do you find Emitter Current when you know the other values?

Rearrange for Emitter Current: with Emitter Resistance 1 Ω, Thermal Voltage 10 mV, Emitter Current is 10 mA.

What units does Small-Signal Emitter Resistance use?

Emitter Resistance is shown in mΩ, Ω, kΩ. Values are held in SI base units internally, so you can mix prefixes without converting by hand.