Force Between Parallel Wires
F/L = µ0 · I1 · I2 / (2π · d)
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Result
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Formula
F/L = µ₀ × I1 × I2 / (2π × d)
Description
Two parallel current-carrying conductors exert a force per unit length on each other through their magnetic fields. Currents in the same direction attract; opposite currents repel. This effect once defined the ampere itself and is the source of the mechanical stress that high-current busbars and fault currents place on conductors.
Variables
- F/L — Force per unit length (N/m)
- I1, I2 — Currents in the two wires (A)
- d — Separation between wires (m)
- µ₀ = 4π×10⁻⁷ H/m —
Practical Notes
During a short-circuit fault, busbars can see thousands of amps and large attractive/repulsive forces—mechanical bracing must be rated for it. Twisting or transposing conductors reduces the net force.
Related Concepts
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