Force on a Current-Carrying Wire

F = B · I · L · sin(θ)

Quick answer

This calculator solves F = B × I × L × sin(θ) for Force. With Flux Density 0.5 T, Current 2 A, Conductor Length 10 cm, Angle I to B 45 °, the result is 70.71 mN. It solves in 4 directions, so you can enter the values you have and get the one you need.

Calculator

Force (N)
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Formula

F = B × I × L × sin(θ)

Description

A wire carrying current in a magnetic field experiences a force equal to the field times the current times the length of conductor in the field, scaled by the sine of the angle between current and field. This is the motor principle: it converts electrical current into mechanical force. The direction is given by the right-hand (or Fleming’s left-hand) rule.

Variables

  • F — Force on the conductor (N)
  • B — Magnetic flux density (T)
  • I — Current (A)
  • L — Length of conductor in the field (m)
  • θ — Angle between current and field (degrees)

Practical Notes

Force is maximum when the wire is perpendicular to the field (θ = 90°). This force times radius gives motor torque; it is also the loudspeaker drive force on the voice coil.

Symbols and units

Symbol Meaning Default unit Accepted units
F Force N µN, mN, N, kN
B Flux Density T G, mT, T
I Current A pA, nA, µA, mA, A, kA
L Conductor Length cm mm, cm, m, km
theta Angle I to B ° °

Step by step

  1. 1. What you know: Flux Density 0.5 T, Current 2 A, Conductor Length 10 cm, Angle I to B 45 °
  2. 2. The relation: F = B × I × L × sin(θ)
  3. 3. Substitute: B = 0.5 T, I = 2 A, L = 10 cm, theta = 45 °
  4. 4. Result: Force = 70.71 mN

Worked examples

Minimum range

Given: Flux Density 10 G, Current 2 mA, Conductor Length 1 mm, Angle I to B 1.5 °

Result: Force = 5.24 × 10⁻⁵ µN

Low range

Given: Flux Density 10 mT, Current 20 mA, Conductor Length 10 mm, Angle I to B 15 °

Result: Force = 0.5176 µN

Typical

Given: Flux Density 0.5 T, Current 2 A, Conductor Length 10 cm, Angle I to B 45 °

Result: Force = 70.71 mN

High range

Given: Flux Density 1.5 T, Current 100 A, Conductor Length 1 m, Angle I to B 75 °

Result: Force = 144.9 N

Maximum range

Given: Flux Density 15 T, Current 1 kA, Conductor Length 10 m, Angle I to B 750 °

Result: Force = 75 kN

Solving for each variable

Solve for Force

Flux Density 10 G, Current 2 mA, Conductor Length 1 mm, Angle I to B 1.5 ° → 5.24 × 10⁻⁵ µN

Solve for Flux Density

Force 1 mN, Current 2 mA, Conductor Length 1 mm, Angle I to B 1.5 ° → 19100 T

Solve for Current

Force 1 mN, Flux Density 10 G, Conductor Length 1 mm, Angle I to B 1.5 ° → 38.2 kA

Solve for Conductor Length

Force 1 mN, Flux Density 10 G, Current 2 mA, Angle I to B 1.5 ° → 19.1 km

How Force changes with Flux Density

Flux Density (input) Force (result)
50 mT 7.071 mN
125 mT 17.68 mN
0.25 T 35.36 mN
0.375 T 53.03 mN
0.5 T 70.71 mN
0.75 T 106.1 mN
1 T 141.4 mN
2 T 0.2828 N
3.5 T 0.495 N
5 T 0.7071 N

The same result in other units

Unit Value
µN 70710
mN 70.71
N 0.07071

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Frequently asked questions

How do you calculate Force on a Current-Carrying Wire?

Use F = B × I × L × sin(θ). With Flux Density 0.5 T, Current 2 A, Conductor Length 10 cm, Angle I to B 45 °, Force works out to 70.71 mN.

What is the formula for Force on a Current-Carrying Wire?

The formula is F = B × I × L × sin(θ). A wire carrying current in a magnetic field experiences a force equal to the field times the current times the length of conductor in the field, scaled by the sine of the angle between current and field.

How do you find Flux Density when you know the other values?

Rearrange for Flux Density: with Force 1 mN, Current 2 mA, Conductor Length 1 mm, Angle I to B 1.5 °, Flux Density is 19100 T.

How do you find Current when you know the other values?

Rearrange for Current: with Force 1 mN, Flux Density 10 G, Conductor Length 1 mm, Angle I to B 1.5 °, Current is 38.2 kA.

What units does Force on a Current-Carrying Wire use?

Force is shown in µN, mN, N. Values are held in SI base units internally, so you can mix prefixes without converting by hand.