JFET Drain Current (Shockley)

Id = Idss · (1 − Vgs/Vp)²

Quick answer

This calculator solves Id = Idss × (1 − Vgs/Vp)² for Drain Current. With Idss 44 mA, Gate-Source Voltage 12 V, Pinch-off Voltage 26.4 V, the result is 13.09 mA. It solves in 4 directions, so you can enter the values you have and get the one you need.

Calculator

Drain Current (mA)
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Formula

Id = Idss × (1 − Vgs/Vp)²

Description

Shockley’s equation gives the drain current of a JFET in saturation as a function of gate–source voltage. The current is maximum (Idss) at zero gate voltage and falls to zero as Vgs approaches the pinch-off (threshold) voltage. The square-law relationship gives JFETs their characteristic soft, low-distortion transfer curve used in audio and RF front ends.

Variables

  • Id — Drain current (A)
  • Idss — Drain current at Vgs = 0 (A)
  • Vgs — Gate-source voltage (V)
  • Vp — Pinch-off / cutoff voltage (V)

Practical Notes

For an n-channel JFET both Vgs and Vp are negative. The transconductance is gm = (2·Idss/|Vp|)·(1 − Vgs/Vp), largest near Vgs = 0.

Symbols and units

Symbol Meaning Default unit Accepted units
Id Drain Current mA pA, nA, µA, mA, A, kA
Idss Idss mA pA, nA, µA, mA, A, kA
Vgs Gate-Source Voltage V pV, nV, µV, mV, V, kV
Vp Pinch-off Voltage V pV, nV, µV, mV, V, kV

Step by step

  1. 1. What you know: Idss 44 mA, Gate-Source Voltage 12 V, Pinch-off Voltage 26.4 V
  2. 2. The relation: Id = Idss × (1 − Vgs/Vp)²
  3. 3. Substitute: Idss = 44 mA, Vgs = 12 V, Vp = 26.4 V
  4. 4. Result: Drain Current = 13.09 mA

Related quantities from the same inputs

  • P = V × I = 0.528 W

Worked examples

Minimum range

Given: Idss 0.22 mA, Gate-Source Voltage 0.33 V, Pinch-off Voltage 0.726 V

Result: Drain Current = 65.45 µA

Low range

Given: Idss 2.2 mA, Gate-Source Voltage 3.3 V, Pinch-off Voltage 7.26 V

Result: Drain Current = 0.6545 mA

Typical

Given: Idss 44 mA, Gate-Source Voltage 12 V, Pinch-off Voltage 26.4 V

Result: Drain Current = 13.09 mA

High range

Given: Idss 1.1 A, Gate-Source Voltage 0.23 kV, Pinch-off Voltage 0.506 kV

Result: Drain Current = 0.3273 A

Maximum range

Given: Idss 11 A, Gate-Source Voltage 2.3 kV, Pinch-off Voltage 5.06 kV

Result: Drain Current = 3.273 A

Solving for each variable

Solve for Drain Current

Idss 0.22 mA, Gate-Source Voltage 0.33 V, Pinch-off Voltage 0.726 V → 65.45 µA

Solve for Idss

Drain Current 100 µA, Gate-Source Voltage 0.33 V, Pinch-off Voltage 0.726 V → 0.3361 mA

Solve for Gate-Source Voltage

Drain Current 100 µA, Idss 0.22 mA, Pinch-off Voltage 0.726 V → 0.2365 V

Solve for Pinch-off Voltage

Drain Current 100 µA, Idss 0.22 mA, Gate-Source Voltage 0.33 V → 1.013 V

How Drain Current changes with Idss

Idss (input) Drain Current (result)
4.4 mA 1.309 mA
11 mA 3.273 mA
22 mA 6.545 mA
33 mA 9.818 mA
44 mA 13.09 mA
66 mA 19.64 mA
88 mA 26.18 mA
0.176 A 52.36 mA
0.308 A 91.64 mA
0.44 A 130.9 mA

The same result in other units

Unit Value
µA 13090
mA 13.09
A 0.01309

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Frequently asked questions

How do you calculate JFET Drain Current (Shockley)?

Use Id = Idss × (1 − Vgs/Vp)². With Idss 44 mA, Gate-Source Voltage 12 V, Pinch-off Voltage 26.4 V, Drain Current works out to 13.09 mA.

How do you calculate calculate the drain current for idss ​= 8ma, vp = −4 v and vgs = −2 v?

Rearrange for Drain Current: with Idss 2.2 mA, Gate-Source Voltage 3.3 V, Pinch-off Voltage 7.26 V, Drain Current is 0.6545 mA.

What is the formula for JFET Drain Current (Shockley)?

The formula is Id = Idss × (1 − Vgs/Vp)². Shockley’s equation gives the drain current of a JFET in saturation as a function of gate–source voltage.

How do you find Idss when you know the other values?

Rearrange for Idss: with Drain Current 100 µA, Gate-Source Voltage 0.33 V, Pinch-off Voltage 0.726 V, Idss is 0.3361 mA.

How do you find Gate-Source Voltage when you know the other values?

Rearrange for Gate-Source Voltage: with Drain Current 100 µA, Idss 0.22 mA, Pinch-off Voltage 0.726 V, Gate-Source Voltage is 0.2365 V.

What units does JFET Drain Current (Shockley) use?

Drain Current is shown in µA, mA, A. Values are held in SI base units internally, so you can mix prefixes without converting by hand.