ADC SNR Limited by Clock Jitter
SNR = −20 · log10(2π · f · tj)
Quick answer
This calculator solves SNR = −20 × log10(2π × f × tj) for SNR. With Input Frequency 10 MHz, RMS Jitter 100 ps, the result is 44.04 dB. It solves in 3 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
Sample-clock jitter sets a hard ceiling on the signal-to-noise ratio of a high-speed ADC, independent of its resolution. Because the error from sampling at the wrong instant grows with the input slew rate, the jitter-limited SNR falls as the input frequency rises. For fast inputs this term, not quantization, dominates—so a low-jitter clock is essential for high-resolution high-frequency digitising.
Variables
- SNR — Jitter-limited signal-to-noise ratio (dB)
- f — Analog input frequency (Hz)
- tj — RMS aperture/clock jitter (s)
Practical Notes
This SNR combines (root-sum-square) with the quantization and thermal-noise limits; the smallest dominates. To digitise a 70 MHz IF at 12-bit SNR you need roughly 1 ps or better clock jitter.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| SNR | SNR | dB | dB |
| f | Input Frequency | MHz | Hz, kHz, MHz, GHz |
| tj | RMS Jitter | ps | ps, ns, µs, ms, s, min, h |
Step by step
- 1. What you know: Input Frequency 10 MHz, RMS Jitter 100 ps
- 2. The relation: SNR = −20 × log10(2π × f × tj)
- 3. Substitute: f = 10 MHz, tj = 100 ps
- 4. Result: SNR = 44.04 dB
Worked examples
Minimum range
Given: Input Frequency 100 kHz, RMS Jitter 1 ps
Result: SNR = 124 dB
Low range
Given: Input Frequency 1 MHz, RMS Jitter 10 ps
Result: SNR = 84.04 dB
Typical
Given: Input Frequency 10 MHz, RMS Jitter 100 ps
Result: SNR = 44.04 dB
High range
Given: Input Frequency 100 MHz, RMS Jitter 0.5 ns
Result: SNR = 10.06 dB
Maximum range
Given: Input Frequency 1 GHz, RMS Jitter 5 ns
Result: SNR = -29.94 dB
Solving for each variable
Solve for SNR
Input Frequency 100 kHz, RMS Jitter 1 ps → 124 dB
Solve for Input Frequency
SNR 0.3 dB, RMS Jitter 1 ps → 153.8 GHz
Solve for RMS Jitter
SNR 0.3 dB, Input Frequency 100 kHz → 1.538 µs
How SNR changes with Input Frequency
| Input Frequency (input) | SNR (result) |
|---|---|
| 1 MHz | 64.04 dB |
| 2.5 MHz | 56.08 dB |
| 5 MHz | 50.06 dB |
| 7.5 MHz | 46.54 dB |
| 10 MHz | 44.04 dB |
| 15 MHz | 40.51 dB |
| 20 MHz | 38.02 dB |
| 40 MHz | 32 dB |
| 70 MHz | 27.13 dB |
| 100 MHz | 24.04 dB |
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<p><a href="https://vbatpower.com/formulas/adc-snr-jitter/">ADC SNR Limited by Clock Jitter</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate ADC SNR Limited by Clock Jitter?
Use SNR = −20 × log10(2π × f × tj). With Input Frequency 10 MHz, RMS Jitter 100 ps, SNR works out to 44.04 dB.
What is the formula for ADC SNR Limited by Clock Jitter?
The formula is SNR = −20 × log10(2π × f × tj). Sample-clock jitter sets a hard ceiling on the signal-to-noise ratio of a high-speed ADC, independent of its resolution.
How do you find Input Frequency when you know the other values?
Rearrange for Input Frequency: with SNR 0.3 dB, RMS Jitter 1 ps, Input Frequency is 153.8 GHz.
How do you find RMS Jitter when you know the other values?
Rearrange for RMS Jitter: with SNR 0.3 dB, Input Frequency 100 kHz, RMS Jitter is 1.538 µs.
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