Common-Source JFET Gain
Av = −gm · Rd
Quick answer
This calculator solves Av = −gm × Rd for Voltage Gain. With Transconductance 10 mS, Drain Resistor 10 kΩ, the result is -100. It solves in 3 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
The voltage gain of a common-source FET amplifier is the device transconductance times the drain load resistance, inverting. Because a FET’s gm is lower than a comparable BJT’s, common-source gains are modest, but the very high input impedance of the gate makes FET stages ideal as low-loading front ends and high-impedance buffers.
Variables
- Av — Voltage gain (negative = inverting)
- gm — Transconductance (S)
- Rd — Drain load resistance (Ω)
Practical Notes
With a source degeneration resistor Rs, Av = −gm·Rd/(1 + gm·Rs), which linearises the stage. FET gm depends on bias current, so gain varies with operating point.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| Av | Voltage Gain | — | — |
| gm | Transconductance | mS | µS, mS, S |
| Rd | Drain Resistor | kΩ | mΩ, Ω, kΩ, MΩ |
Step by step
- 1. What you know: Transconductance 10 mS, Drain Resistor 10 kΩ
- 2. The relation: Av = −gm × Rd
- 3. Substitute: gm = 10 mS, Rd = 10 kΩ
- 4. Result: Voltage Gain = -100
Worked examples
Minimum range
Given: Transconductance 100 µS, Drain Resistor 100 Ω
Result: Voltage Gain = -0.01
Low range
Given: Transconductance 1 mS, Drain Resistor 1 kΩ
Result: Voltage Gain = -1
Typical
Given: Transconductance 10 mS, Drain Resistor 10 kΩ
Result: Voltage Gain = -100
High range
Given: Transconductance 100 mS, Drain Resistor 100 kΩ
Result: Voltage Gain = -10000
Maximum range
Given: Transconductance 1 S, Drain Resistor 1 MΩ
Result: Voltage Gain = -1 × 10⁶
Solving for each variable
Solve for Voltage Gain
Transconductance 100 µS, Drain Resistor 100 Ω → -0.01
Solve for Transconductance
Voltage Gain 0.025, Drain Resistor 100 Ω → -0.25 mS
Solve for Drain Resistor
Voltage Gain 0.025, Transconductance 100 µS → -0.25 kΩ
How Voltage Gain changes with Transconductance
| Transconductance (input) | Voltage Gain (result) |
|---|---|
| 1 mS | -10 |
| 2.5 mS | -25 |
| 5 mS | -50 |
| 7.5 mS | -75 |
| 10 mS | -100 |
| 15 mS | -150 |
| 20 mS | -200 |
| 40 mS | -400 |
| 70 mS | -700 |
| 100 mS | -1000 |
Embed this calculator
Paste this into any page. It keeps working when this page updates, and credits the source.
<iframe src="https://vbatpower.com/embed/cs-jfet-gain/" width="100%" height="460" style="border:1px solid #1f2a37;border-radius:12px" loading="lazy" title="Common-Source JFET Gain"></iframe>
<p><a href="https://vbatpower.com/formulas/cs-jfet-gain/">Common-Source JFET Gain</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate Common-Source JFET Gain?
Use Av = −gm × Rd. With Transconductance 10 mS, Drain Resistor 10 kΩ, Voltage Gain works out to -100.
How do you calculate jfet common source amplifier gain calculation?
Rearrange for Voltage Gain: with Transconductance 1 mS, Drain Resistor 1 kΩ, Voltage Gain is -1.
What is the formula for Common-Source JFET Gain?
The formula is Av = −gm × Rd. The voltage gain of a common-source FET amplifier is the device transconductance times the drain load resistance, inverting.
How do you find Transconductance when you know the other values?
Rearrange for Transconductance: with Voltage Gain 0.025, Drain Resistor 100 Ω, Transconductance is -0.25 mS.
How do you find Drain Resistor when you know the other values?
Rearrange for Drain Resistor: with Voltage Gain 0.025, Transconductance 100 µS, Drain Resistor is -0.25 kΩ.
Related Concepts
All Discrete Amplifiers formulas →Need more features?
Save calculations, import telemetry data, simulate battery discharge, and collaborate with your team.
Try the App