RC Low-Pass Filter
fc = 1 / (2πRC)
Quick answer
This calculator solves fc = 1 / (2πRC) for Cutoff Frequency. With Resistance 10 kΩ, Capacitance 100 nF, the result is 0.1592 kHz. It solves in 3 directions, so you can enter the values you have and get the one you need.
Calculator
Formula
Description
A first-order RC low-pass filter passes signals below the cutoff frequency and attenuates signals above it. The cutoff frequency (also called the -3dB point or corner frequency) is where the output amplitude drops to 70.7% of the input (half power). Above this frequency, attenuation increases at 20 dB per decade (6 dB per octave). The filter consists of a series resistor followed by a capacitor to ground. At low frequencies, the capacitor impedance is high and most of the signal passes through. At high frequencies, the capacitor becomes a low impedance path to ground, shunting the signal.
Variables
- fc — Cutoff frequency at -3dB point (Hz)
- R — Resistance (Ω)
- C — Capacitance (F)
Practical Notes
First-order RC filters are used for anti-aliasing before ADCs, power supply decoupling, smoothing PWM signals into analog voltages, and removing high-frequency noise from sensor signals. For steeper rolloff, cascade multiple stages or use active filter topologies (Sallen-Key, multiple feedback). The phase shift at fc is -45 degrees.
Symbols and units
| Symbol | Meaning | Default unit | Accepted units |
|---|---|---|---|
| fc | Cutoff Frequency | kHz | Hz, kHz, MHz, GHz |
| R | Resistance | kΩ | mΩ, Ω, kΩ, MΩ |
| C | Capacitance | nF | pF, nF, µF, mF, F |
Step by step
- 1. What you know: Resistance 10 kΩ, Capacitance 100 nF
- 2. The relation: fc = 1 / (2πRC)
- 3. Substitute: R = 10 kΩ, C = 100 nF
- 4. Result: Cutoff Frequency = 0.1592 kHz
Worked examples
Minimum range
Given: Resistance 100 Ω, Capacitance 100 pF
Result: Cutoff Frequency = 15.92 MHz
Low range
Given: Resistance 1 kΩ, Capacitance 1 nF
Result: Cutoff Frequency = 0.1592 MHz
Typical
Given: Resistance 10 kΩ, Capacitance 100 nF
Result: Cutoff Frequency = 0.1592 kHz
High range
Given: Resistance 100 kΩ, Capacitance 1 µF
Result: Cutoff Frequency = 1.592 Hz
Maximum range
Given: Resistance 1 MΩ, Capacitance 10 µF
Result: Cutoff Frequency = 0.01592 Hz
Solving for each variable
Solve for Cutoff Frequency
Resistance 100 Ω, Capacitance 100 pF → 15.92 MHz
Solve for Resistance
Cutoff Frequency 100 Hz, Capacitance 100 pF → 15.92 MΩ
Solve for Capacitance
Cutoff Frequency 100 Hz, Resistance 100 Ω → 15.92 µF
How Cutoff Frequency changes with Resistance
| Resistance (input) | Cutoff Frequency (result) |
|---|---|
| 1 kΩ | 1.592 kHz |
| 2.5 kΩ | 0.6366 kHz |
| 5 kΩ | 0.3183 kHz |
| 7.5 kΩ | 0.2122 kHz |
| 10 kΩ | 0.1592 kHz |
| 15 kΩ | 106.1 Hz |
| 20 kΩ | 79.58 Hz |
| 40 kΩ | 39.79 Hz |
| 70 kΩ | 22.74 Hz |
| 100 kΩ | 15.92 Hz |
The same result in other units
| Unit | Value |
|---|---|
| Hz | 159.2 |
| kHz | 0.1592 |
| MHz | 0.0001592 |
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<p><a href="https://vbatpower.com/formulas/lowpass-rc/">RC Low-Pass Filter</a> Calculator by vbatpower.com</p> Frequently asked questions
How do you calculate RC Low-Pass Filter?
Use fc = 1 / (2πRC). With Resistance 10 kΩ, Capacitance 100 nF, Cutoff Frequency works out to 0.1592 kHz.
What is the formula for RC Low-Pass Filter?
The formula is fc = 1 / (2πRC). A first-order RC low-pass filter passes signals below the cutoff frequency and attenuates signals above it.
How do you find Resistance when you know the other values?
Rearrange for Resistance: with Cutoff Frequency 100 Hz, Capacitance 100 pF, Resistance is 15.92 MΩ.
How do you find Capacitance when you know the other values?
Rearrange for Capacitance: with Cutoff Frequency 100 Hz, Resistance 100 Ω, Capacitance is 15.92 µF.
What units does RC Low-Pass Filter use?
Cutoff Frequency is shown in Hz, kHz, MHz. Values are held in SI base units internally, so you can mix prefixes without converting by hand.
Related Concepts
All Filters formulas →Need more features?
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