Skin Depth

δ = 1 / √(πfμσ)

Quick answer

This calculator solves δ = 1 / √(πfμσ) for δ. With Frequency 10 MHz, Permeability (H/m) 0.001 H/m, Conductivity (S/m) 1 × 10⁶ S/m, the result is 5.64 × 10⁻⁶ m.

Calculator

Result
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Formula

δ = 1 / √(πfμσ)

Description

At high frequencies, alternating current concentrates near the surface of a conductor due to eddy currents generated by the changing magnetic field. The skin depth is the distance from the surface at which the current density drops to 1/e (about 37%) of its surface value. Beyond about 3-5 skin depths, virtually no current flows. This effect increases the effective resistance of conductors at high frequencies because less of the cross-sectional area is utilized. Skin effect is a major design consideration for RF circuits, power transmission at 50/60Hz, and high-speed digital signal traces.

Variables

  • δ — Skin depth (m)
  • f — Frequency (Hz)
  • μ — Permeability of the conductor (H/m)
  • σ — Conductivity of the conductor (S/m)

Practical Notes

For copper at room temperature (σ = 5.8×10⁷ S/m, μ = μ₀): skin depth at 60 Hz is 8.5mm, at 1 MHz is 66μm, at 1 GHz is 2.1μm. This is why RF PCB traces only need to be a few skin depths thick. Litz wire (bundles of thin insulated strands) is used at kHz-MHz frequencies to mitigate skin effect losses in inductors and transformers.

Symbols and units

Symbol Meaning Default unit Accepted units
f Frequency MHz Hz, kHz, MHz, GHz
mu Permeability (H/m) H/m H/m
sigma Conductivity (S/m) S/m S/m

Step by step

  1. 1. What you know: Frequency 10 MHz, Permeability (H/m) 0.001 H/m, Conductivity (S/m) 1 × 10⁶ S/m
  2. 2. The relation: δ = 1 / √(πfμσ)
  3. 3. Substitute: f = 10 MHz, mu = 0.001 H/m, sigma = 1 × 10⁶ S/m
  4. 4. Result: δ = 5.64 × 10⁻⁶ m

Worked examples

Minimum range

Given: Frequency 100 kHz, Permeability (H/m) 1 × 10⁻⁷ H/m, Conductivity (S/m) 1000 S/m

Result: δ = 0.1784 m

Low range

Given: Frequency 1 MHz, Permeability (H/m) 1 × 10⁻⁶ H/m, Conductivity (S/m) 10000 S/m

Result: δ = 0.005642 m

Typical

Given: Frequency 10 MHz, Permeability (H/m) 0.001 H/m, Conductivity (S/m) 1 × 10⁶ S/m

Result: δ = 5.64 × 10⁻⁶ m

High range

Given: Frequency 100 MHz, Permeability (H/m) 1 H/m, Conductivity (S/m) 5.8 × 10⁷ S/m

Result: δ = 7.41 × 10⁻⁹ m

Maximum range

Given: Frequency 1 GHz, Permeability (H/m) 10 H/m, Conductivity (S/m) 5.8 × 10⁸ S/m

Result: δ = 2.34 × 10⁻¹⁰ m

How δ changes with Frequency

Frequency (input) δ (result)
1 MHz 1.78 × 10⁻⁵ m
2.5 MHz 1.13 × 10⁻⁵ m
5 MHz 7.98 × 10⁻⁶ m
7.5 MHz 6.51 × 10⁻⁶ m
10 MHz 5.64 × 10⁻⁶ m
15 MHz 4.61 × 10⁻⁶ m
20 MHz 3.99 × 10⁻⁶ m
40 MHz 2.82 × 10⁻⁶ m
70 MHz 2.13 × 10⁻⁶ m
100 MHz 1.78 × 10⁻⁶ m

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Frequently asked questions

How do you calculate Skin Depth?

Use δ = 1 / √(πfμσ). With Frequency 10 MHz, Permeability (H/m) 0.001 H/m, Conductivity (S/m) 1 × 10⁶ S/m, δ works out to 5.64 × 10⁻⁶ m.

What is the formula for Skin Depth?

The formula is δ = 1 / √(πfμσ). At high frequencies, alternating current concentrates near the surface of a conductor due to eddy currents generated by the changing magnetic field.

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