RC Phase-Shift Oscillator Frequency

f = 1 / (2π · R · C · √6)

Quick answer

This calculator solves f = 1 / (2π × R × C × √6) for Frequency. With Resistance 10 kΩ, Capacitance 100 nF, the result is 64.97 Hz. It solves in 3 directions, so you can enter the values you have and get the one you need.

Calculator

Frequency (kHz)
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Formula

f = 1 / (2π × R × C × √6)

Description

An RC phase-shift oscillator uses three cascaded RC sections to provide the 180° of phase shift needed (together with the inverting amplifier’s 180°) for oscillation. With three equal sections the oscillation frequency includes the √6 factor. The amplifier must make up the network’s loss, which for the three-section case requires a voltage gain of at least 29.

Variables

  • f — Oscillation frequency (Hz)
  • R — Resistance of each section (Ω)
  • C — Capacitance of each section (F)

Practical Notes

The loop attenuation at the oscillation frequency is 1/29, so the amplifier gain must be ≥ 29. More sections lower the required gain but complicate tuning. Best for fixed audio-frequency sine generation.

Symbols and units

Symbol Meaning Default unit Accepted units
f Frequency kHz Hz, kHz, MHz, GHz
R Resistance kΩ mΩ, Ω, kΩ, MΩ
C Capacitance nF pF, nF, µF, mF, F

Step by step

  1. 1. What you know: Resistance 10 kΩ, Capacitance 100 nF
  2. 2. The relation: f = 1 / (2π × R × C × √6)
  3. 3. Substitute: R = 10 kΩ, C = 100 nF
  4. 4. Result: Frequency = 64.97 Hz

Worked examples

Minimum range

Given: Resistance 100 Ω, Capacitance 100 pF

Result: Frequency = 6.497 MHz

Low range

Given: Resistance 1 kΩ, Capacitance 1 nF

Result: Frequency = 64.97 kHz

Typical

Given: Resistance 10 kΩ, Capacitance 100 nF

Result: Frequency = 64.97 Hz

High range

Given: Resistance 100 kΩ, Capacitance 1 µF

Result: Frequency = 0.6497 Hz

Maximum range

Given: Resistance 1 MΩ, Capacitance 10 µF

Result: Frequency = 0.006497 Hz

Solving for each variable

Solve for Frequency

Resistance 100 Ω, Capacitance 100 pF → 6.497 MHz

Solve for Resistance

Frequency 100 Hz, Capacitance 100 pF → 6.497 MΩ

Solve for Capacitance

Frequency 100 Hz, Resistance 100 Ω → 6.497 µF

How Frequency changes with Resistance

Resistance (input) Frequency (result)
1 kΩ 0.6497 kHz
2.5 kΩ 0.2599 kHz
5 kΩ 129.9 Hz
7.5 kΩ 86.63 Hz
10 kΩ 64.97 Hz
15 kΩ 43.32 Hz
20 kΩ 32.49 Hz
40 kΩ 16.24 Hz
70 kΩ 9.282 Hz
100 kΩ 6.497 Hz

The same result in other units

Unit Value
Hz 64.97
kHz 0.06497

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Frequently asked questions

How do you calculate RC Phase-Shift Oscillator Frequency?

Use f = 1 / (2π × R × C × √6). With Resistance 10 kΩ, Capacitance 100 nF, Frequency works out to 64.97 Hz.

What is the formula for RC Phase-Shift Oscillator Frequency?

The formula is f = 1 / (2π × R × C × √6). An RC phase-shift oscillator uses three cascaded RC sections to provide the 180° of phase shift needed (together with the inverting amplifier’s 180°) for oscillation.

How do you find Resistance when you know the other values?

Rearrange for Resistance: with Frequency 100 Hz, Capacitance 100 pF, Resistance is 6.497 MΩ.

How do you find Capacitance when you know the other values?

Rearrange for Capacitance: with Frequency 100 Hz, Resistance 100 Ω, Capacitance is 6.497 µF.

What units does RC Phase-Shift Oscillator Frequency use?

Frequency is shown in Hz, kHz. Values are held in SI base units internally, so you can mix prefixes without converting by hand.

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